Here's a graph of the function: Note that it is the cosine function, but stretched in the vertical direction by the factor $2$ and “compressed” in the horizontal direction by the factor $3$.

Feb 18, 2013 · 1 Critical points are not where the function is $0.$ You want to find the points where the derivative is $0.$ Unfortunately, your function does not happen to be differentiable …

I thought that to find the critical points, I have to find the 1st derivative and to find local max/min or saddle, I have to use the second derivative test. I am having a little trouble both in finding first …

Feb 3, 2019 · A critical point is a point where the derivative of a function is either zero (there is going to be a horizontal tangent line to the curve at that point) or does not exist (it's not …

Not all quadratic equations factor so nicely. This is when the "quadratic formula" comes in handy. A quick check of the sign of the discriminant will tell you if there rational, even if there are real, …

Oct 7, 2021 · Using the second condition gave me 2 other critical points: $ (-1,\frac {1} {2})$ and $ (-1,-\frac {1} {2})$ So now that I know what are the critical points, I want to classify them (local …

I am having difficulties in understanding the steps/method required to find the critical points of a function using the method of Lagrange multipliers. I have read through my text book and tried …

to find the critical points of this function, you can either do f' (x) = 0 directly using the chain rule or you can note the following: Please consider the following:

Finding critical points of f (x,y) Ask Question Asked 13 years, 2 months ago Modified 2 years, 5 months ago

Jul 2, 2014 · Usually you would define a "critical point" as the zero-points of the first derivative of your function. Since this functions first derivative has no zero-point, the critical point you …